Question

The sides of a triangular field are 51 cm, 37 cm & 20 cm , find the Rose beds that can be prepared by the field if each Rose beds occupies the space 6cm^2.

Answer 1

semi perimeter=51+37+20÷2

s=108÷2=54cm

s-a=54-51=3cm

s-b=54-37=17cm

s-c=54-20=34cm

$area \: of \: the \: triangle = \sqrt{s(s - a)(s - b)(s - c)} sq \: units$

=

$\sqrt{54 \times 3 \times 17 \times 34}$

=

$\sqrt{3 \times 3 \times 3 \times 3 \times 17 \times 17 \times 2 \times 2}$

$= 3 \times 3 \times 17 \times 2$

=306 cm sq

area required for 1 rose bed=6 cm Sq

no.of rose beds in 1 cm sq=1/6

no. of rose beds in 306 cm sq =306×1/6

=51

Answer 2

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