The sides of a triangular field are 7 m , 15m and 20 m . find the number of rose beds that can be prepared in the field , if each , rose bed, on an average needs 200 cm ^2 space.
Answers
Answer:
There can be 2100 rosebeds in the triangular field.
Step-by-step explanation:
Sides of triangle = 7 m, 15 m and 20 m
A rose bed needs area of = 200 cm² = 0.02 m²
_______________________
Find the area of triangle. Using the Heron's Formula,
- a = 7 m
- b = 15 m
- c = 20 m
Semi Perimeter is 21 m.
_______________________
Heron's Formula,
- s = 21 m
- a = 7 m
- b = 15 m
- c = 20 m
Area of triangle = 42 m²
_______________________
Number of rose beds =
- Area of triangle = 42 m²
- Area of a rose bed = 0.02 m²
Number of rose beds = 2100
Therefore, there can be 2100 rosebeds in the triangular field.
Answer:
Given :-
The side of a triangular field are 7 m , 15m and 20 m .
To Find :-
Number of rose bed can be prepared
Solution :-
According to the question
Area of triangle = a + b + c/2
Semiperimeter = 7 + 15 + 20/2
Semiperimeter = 42/2
Semiperimeter = 21 m
Now
Area = √s(s - a)(s - b)(s - c)
Area = √21(21 - 7)(21 - 15)(21 - 20)
Area = √21 × 14 × 6 × 1
Area = √1764
Area = 42 m²
Now
1 m² = 10,000 cm²
No. of rose bed may made = 42/200/10,000
No. of rose bed may made = 42/200 × 10000
No. of rose bed may made = 2100