The sides of a triangular field are 7 m , 15m and 20 m . find the number of rose beds that can be prepared in the field , if each , rose bed, on an average needs 200 cm ^2 space.
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Answers
Answered by
15
Given :-
The side of a triangular field are 7 m , 15m and 20 m .
To Find :-
Number of rose bed can be prepared
Answer
Area of triangle = a + b + c/2
Semiperimeter = 7 + 15 + 20/2
Semiperimeter = 42/2
Semiperimeter = 21 m
Now
Area = √s(s - a)(s - b)(s - c)
Area = √21(21 - 7)(21 - 15)(21 - 20)
Area = √21 × 14 × 6 × 1
Area = √1764
Area = 42 m²
Now
1 m² = 10,000 cm²
No. of rose bed may made = 42/200/10,000
No. of rose bed may made = 42/200 × 10000
No. of rose bed may made = 2100
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Answered by
1
When path built then the new radius
become = 42+3.5 = 45.5m
Now
Cost = Area×Rate
Let the old radius be 'r' and new radius be 'R'
Area of the garden
π(R² - r²)
22/7(45.5² - 42²)
22/7 × (2070.25 - 1764)
22/7 × 306.25
9625m.
Now
Cost = Rrea× Rate
Cost = 962.5×20
Cost = 19250
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