Question

The sides of a triangular park are in the ratio 1 : 2 : 3. The perimeter of the triangular park is 144 m.

find the longest side.​

Answer 1

Answer:

perimeter of a triangular field is 144 m and the ratio of the sides is 3 4 5 find the area of ... Let a, b, c be the lengths of the sides of the triangular field. = K (say) …..(Given) …..(1). Given that perimeter = 144 m.

Answer 2

Answer:

the sides of triangles are 3x,4x and 5x.

And perimeter of the triangle is 144cm.

So , 3x+4x+5x=144

12x=144

x=12

so, the sides are triangle are 3(12)=36cm, 4(12)=48cm , 5(12)=60cm

so , the longest side is 60 cm.

Area of triangle =

s(s−a)(s−b)(s−c)

here , s=72 and a=36, b=48 c=60

=

72(72−36)(72−48)(72−60)

=

72(36)(24)(12)

=

746496

= 864

So, the area of triangle is 864 cm

2

and the height corresponding to longest side h=

60

2×864

=28.8cm