Math, asked by rahulchoudhary210520, 4 months ago

the sides of a triangular park is in the ratio 3:5:7. it's semi perimeter is 150 m find its area​

Answers

Answered by Anonymous
6

Answer :

›»› The area of triangular park is 1500√3 m².

Given :

  • The sides of a triangular park is in the ratio 3:5:7.

To Find :

  • The area of triangular park.

Solution :

Let us assume that, the sides of a triangular park is 3x, 5x, and 7x respectively.

As it is given that the semi perimeter is 150 m.

And their sides are :

  • a = 3x.
  • b = 5x.
  • c = 7x

As we know that

→ s = (a + b + c)/2

→ 150 = (3x + 5x + 7x)/2

→ 150 = (8x + 7x)/2

→ 150 = 15x/2

→ 150 * 2 = 15x

→ 300 = 15x

→ x = 300/15

x = 20

Therefore,

→ a = 3x

→ a = 3 * 20

a = 60

→ b = 5x

→ b = 5 * 20

b = 100

→ c = 7x

→ c = 7 * 20

c = 140

Their sides are 60, 100, and 140.

Now,

As we know that

→ Area = √s(s - a)(s - b)(s - c)

→ Area = √150(150 - 60)(150 - 100)(150 - 140)

→ Area = √150 * 90 * 50 * 10

→ Area = √(150 * 9 * 5) * (10)⁴

→ Area = √15 * (3 * 3) * 5 * 3 * (10)⁴

→ Area = √15 * (3 * 5) * 3 * (10)⁴

→ Area = √15 * 15 * 3 * (10)⁴

→ Area = √(15)² * 3 * (10)⁴

→ Area = √(15)² * √3 * √(10)⁴

→ Area = (15) * √3 * (10⁴)^½

→ Area = (15) * √3 * (10²)

→ Area = 15 * √3 * 1000

Area = 1500√3

Hence, the area of triangular park is 1500√3 m².

Answered by Anonymous
2

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • Ratio of sides of triangular park is 3:5:7

 \:\:

  • Semi perimeter is 150 m

 \:\:

 \red{\underline \bold{To \: Find:}}

 \:\:

  • Area of triangular park

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

 \underline{\bold{\texttt{Area of triangle : }}}

 \:\:

 \bf \dag \ \sqrt {s(s - a)(s - b)(s - c) }

 \:\:

  • s = Semi perimeter

  • a = 1st side

  • b = 2nd side

  • c = 3rd side

 \:\:

Let the sides be 3x , 5x , 7x respectively

 \:\:

 \sf \longmapsto s = 150 \ \ \ \ [ Given ]

 \:\:

Also,

 \:\:

 \sf \longmapsto s = \dfrac { (a + b + c) } { 2 }

 \:\:

 \sf \longmapsto 150 = \dfrac { 3x + 5x + 7x } { 2 }

 \:\:

 \sf \longmapsto 300 = 3x + 5x + 7x

 \:\:

 \sf \longmapsto 300 = 15x

 \:\:

 \bf \dashrightarrow x = 20

 \:\:

  • a = 3 × 20 = 60m

  • b = 5 × 20 = 100m

  • c = 7 × 20 = 140m

 \:\:

 \underline{\bold{\texttt{For area -}}}

 \:\:

 \sf \longmapsto \sqrt {150(150 - 60)(150 - 100)(150 - 140) }

 \:\:

 \sf \longmapsto \sqrt {150(90)(50)(10) }

 \:\:

 \sf \longmapsto \sqrt {6750000 }

 \:\:

 \bf \dashrightarrow 1500 \sqrt 3

 \:\:

  • Hence area will be 1500√3

Or

  • 2598 sq. m [ Approx ]
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