Question

The sides of ∆ABC are 6 cm, 8 cm, and 10 cm. A circumcentre of ∆ABC is drawn. What is the radius of the circumcircle?

Answer 1

Answer:

Given AB=BC=CA=6cm

⇒ We have O as the circumcenter

⇒ ∠OBA=30

o

In △BOM,

⇒ cos30

o

=

BO

BM

⇒

2

3

=

r

3

∴ r=2

3

cm

⇒ Area of shaded region = Area of circle - Area of △ABC

⇒ Area of shaded region =πr

2

−

4

3

×(side)

2

⇒ Area of shaded region =(3.14)×(2

3

)

2

−

4

3

×(6)

2

⇒ Area of shaded region =37.68−15.59

∴ Area of shaded region =22.126cm

2

Step-by-step explanation:

see the image

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