The sides of Δ ABC are produced as shown in the figure, Prove that ∠CBX + ∠ACY + ∠BAZ=360°
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Answered by
38
As we know that
Sum of all external angles of a triangle is 360°
Then
angle CBX +angle ACY +angle BAZ =360°.
Hence proved.
Sum of all external angles of a triangle is 360°
Then
angle CBX +angle ACY +angle BAZ =360°.
Hence proved.
Answered by
15
Answer:
Sum of external angles of a quad is 360°
there fore sum of all these external angles is 360°
hence proved!
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