The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. find the rate at which its area increases, when side is 10 cm long.
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Let the side of equilateral triangle be x cm & area be A . Now ATQ
dx/dt = 2cm/s ,
A = √3/4x²
Differentiating w.r.t "t"
dA/dt = √3/4 × 2x × dx/dt
dA/dt = √3/4 × 20 × 2
dA/dt = 10√3 cm²/s
Let the side of equilateral triangle be x cm & area be A . Now ATQ
dx/dt = 2cm/s ,
A = √3/4x²
Differentiating w.r.t "t"
dA/dt = √3/4 × 2x × dx/dt
dA/dt = √3/4 × 20 × 2
dA/dt = 10√3 cm²/s
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