the sides of an isosceles right triangle of hypotenuse 4√2cm . find the other two sides
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Hypotenuse = 4√2
As it is isosceles right angled triangle, the remaining two sides are equal.
So, base = height
Let the base and height be x
We know that,
hypotenuse² = base² + height²
(4√2)² = x² + x²
16(√2)² = 2x²
16(2) = 2x²
2x² = 32
x² = 32/2
x² = 16
x = √16
x = 4
Therefore, the length of other two sides are 4 i.e., base = height = 4
hope it helps…
As it is isosceles right angled triangle, the remaining two sides are equal.
So, base = height
Let the base and height be x
We know that,
hypotenuse² = base² + height²
(4√2)² = x² + x²
16(√2)² = 2x²
16(2) = 2x²
2x² = 32
x² = 32/2
x² = 16
x = √16
x = 4
Therefore, the length of other two sides are 4 i.e., base = height = 4
hope it helps…
stark26:
thnx
Answered by
6
isosceles traingle have two equal sides ..let it be x
by phythagores theorem
x²+x²=(4√2)²
2x²=32
x²=16
x=4
hence sides of Δ is 4cm
hope this will help u
plzz mark it as brainlist
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