The sides of an isosceles triangle are measured correct to the nearest millimetre.
One side has a length of 8.2cm and another has a length of 9.4cm.
Find the largest possible value of the perimeter of this triangle.
Answers
Answered by
4
Maximum value = 27 cm
It has two possible values
When 8.2 cm is isosceles ,
Perimeter = (2×8.2)+9.4
= 16.4 + 9.4
= 25.8 cm
When 9.4 cm is isosceles,
Perimeter = 8.2 + ( 2×9.4)
= 8.2 + 18.8
= 27 cm
Maximum value = 27 cm
Answered by
2
Answer:
27.12
Step-by-step explanation:
nearest mm of 9.4cm is 94.4mm
nearest mm of 8.2cm is 82.4mm
so largest perimeter = 94.4+94.4+82.4
= 271.2mm
=271.2/10
=27.12cm
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