The sides of certain triangles are given below. Determine which of them are right triangles.
(i) a = 7 cm, b = 24 cm and c = 25 cm
(ii) a = 9 cm, b = 16 cm and c = 18 cm
(iii) a = 1.6 cm, b = 3.8 cm and c = 4 cm
(iv) a = 8 cm, b = 10 cm and c = 6 cm
Answers
SOLUTION :
(i)
Let a = 7 cm , b = 24 cm , c = 25 cm
Here, the larger side is c = 25 cm
c² = (25)² = 625
b² = (24)² = 576
a² = (7)² = 49
By Converse of Pythagoras theorem: In a triangle , if the square of one side is equal to the sum of the squares of the other two sides then the angle opposite to the side is a right angle. (c² = a² + b²)
Here,
c² = a² + b²
625 = 49 + 576
625 = 625
Hence, the triangle with the given sides is a right angled triangle.
(ii)
Let a = 9 cm , b = 16 cm , c = 18 cm
Here, the larger side is c = 18 cm
c² = (18)² = 324
b² = (16)² = 256
a² = (9)² = 81
By Converse of Pythagoras theorem: In a triangle , if the square of one side is equal to the sum of the squares of the other two sides then the angle opposite to the side is a right angle. (c² = a² + b²)
Here,
c² ≠ a² + b²
324 ≠ 81 + 256
324 ≠ 337
Hence, the triangle with the given sides is not a right angled triangle.
(iii)
Let a = 1.6 cm , b = 3.8 cm , c = 4 cm
Here, the larger side is c = 4 cm
c² = (4)² = 16
b² = (3.8)² = 14.44
a² = (1.6)² = 2.56
By Converse of Pythagoras theorem: In a triangle , if the square of one side is equal to the sum of the squares of the other two sides then the angle opposite to the side is a right angle. (c² = a² + b²)
Here,
c² ≠ a² + b²
16 ≠ 2.56 + 14.44
16 ≠ 17
Hence, the triangle with the given sides is not a right angled triangle.
(iv)
Let a = 8 cm , b = 10 cm , c = 6 cm
Here, the larger side is b = 10 cm
c² = (6)² = 36
b² = (10)² = 100
a² = (8)² = 64
By Converse of Pythagoras theorem: In a triangle , if the square of one side is equal to the sum of the squares of the other two sides then the angle opposite to the side is a right angle. (b² = a² + c²)
Here,
b² = a² + c²
100 = 64 + 36
100 = 100
Hence, the triangle with the given sides is a right angled triangle.
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