the sides of hexagon are produced in order. if the measure of exterior angle so obtained are (3x-5), (8x+3), (7x-2), (4x+1), (6x+4) and (2x-1). find the value of x and measure each of the exterior angle of the hexagon.
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Sum of the interior angles of hexagon
= (2n-4) 90° =(2× 6-4)× 90° =720°
(3x-5)+(8x+3)+(7x-2)+(4x+1)+(6x+4)+ (2x-1)=360°
30x=360°
x=12°
Now substitute the value of x in the expressions of all the sides we get:
(3x-5)° =31°
(8x+3)° =99°
(7x-2)° =82°
(4x+1)° =49°
(6x+4)° = 76°
(2x-1)°=23°
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