Question

the sides of park are in ratio 4:3 if its area is 1728 m find the cost of fencing at the rate of rs 3 per metre​

Answer 1

Answer:

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Step-by-step explanation:

let the sides of the park be 4x and 3x

Area of the park = 1728

lenght × breadth = 1728

4x × 3x = 1728

12xsq = 1728

xsq = 1728/12

x = root 144

x = 12

therefore

lenght and breadth = 2×2×3 = 12

hence,

lenght = 4×12=48

breadth = 3×12=36

perimeter = 2(48+36)

= 2×84= 168 m

cost of fencing = rs(168×30)

=rs5040

hope it helped you

Answer 2

Answer:

Solution:-

Let the length be 4x

and breadth be 3x

Area of a Rectangle = length × breadth

⇏2028 = 4x × 3x

⇏12x^2 = 2028

⇏x^2 = 2028/12

= 169

⇏x = √169

= 13

So, length = 4x = 4 × 13 = 52 m

breadth = 3x = 3 × 13 = 39 m

As fencing is done on boundary we have to find the perimeter of he field

⇏2 × ( l + b )

⇏2 × ( 52 + 39 )

⇏182 m

Cost of fencing per metre = Rs.3

Total cost = 182 × 3

= ₹546