the sides of quadrilateral taken in oder are 48cm,46cm,40cm and 9cm respectively the angle between the last two sides is a right angle find area of quadrilateral
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The sides of quadrilateral taken in order are 9m,40m,15m and 28m. If the angle between the first. two sides is a right angle find its area.
December 20, 2019avatar
Shanmugam Padigala
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Say AB=9m,BC=40m,CD=15m,DA=28m
As given that △ABC is a right angle triangle then
AC
2
=9
2
+40
2
AC=41m
Area of △ABC=
2
1
×9×40=180m
2
,
In △ACD,
Perimeter s=
2
15+28+41
=42
Area of △ADC=
s(s−15)(s−28)(s−40)
Area of △ADC=
42(42−15)(42−28)(42−40)
=126m
2
,
Area of ABCD=Area of △ABC+Area of △ACD=180+126=306m
2
.
Answered by
0
Answer:
area = 3434m2
Step-by-step explanation:
34534579
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