the sides of rectalngle are 20 cm and 15 cm. if each side of the rectangle increased by 20% find the percentage increased in the area
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Hey mate...
Here is your answer....
Perimeter of rect. = 2[l+b]
=2 [ 20 cm+15 cm]
= 2 X 35 cm
= 70 cm
Now,
According to question,
each side is increased by 20%
Then,
length = 20 + 20% of 20
= 20 + 4
= 24 cm
and,
breadth = 15 + 20% of 15
= 15 + 3
= 18
So, the new perimeter will be =
2[ 24 +18] cm
= 2 X 42 cm
= 84 cm
Hence, the perimeter of rect. is increased by 14 cm .
Percentage of increasing= 14/70 X 100
= 20 %
Hope it will you....
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Thanks for asking....
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