the sides of rectangle ABCD are 6 cm and 8 cm respectively find the length of the diagonal
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Given:
length of a triangle =8cm
breadth of a triangle = 6cm
by Pythagoras theorem
(hypotenuse)^2=(height)^2+(base)^2
(diagonal)^2=( length)^2 + (breadth)^2
let the diagonal be x cm
x^2= 36+64
x^2 =100
x=10cm
therefore the length of a diagonal = 10cm
Answered by
2
Answer:
Given:
length of a triangle =8cm
breadth of a triangle = 6cm
by Pythagoras theorem
(hypotenuse)^2=(height)^2+(base)^2
(diagonal)^2=( length)^2 + (breadth)^2
let the diagonal be x cm
x^2= 36+64
x^2 =100
x=10cm
therefore the length of a diagonal = 10cm
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