Question

The sides of rectangle are 3a2+6b and 4a2+b find its perimeter

Answer 1

Answer:

Perimeter=2(l+b)

=2(3a−b+6b−a)

=2(5b+2a)

=10b+4a

Answer 2

Step-by-step explanation:

Length of rectangle=3a^2+6b

Breadth or rectangle=4a^2+b

Perimeter of rectangle=2(l+b)

=2(3a^2+4a^2+6b+b)

(ADD LIKE TERMS)

=2(7a^2+7b)

=14a^2+14b

So,the perimeter of rectangle is 14a^2+14b.