Math, asked by kavishsaab39, 11 months ago

the sides of rectangle are in the ratio of 4:5 and it's perimeter is 90 find the dimension of rectangle and hence his area​

Answers

Answered by Anonymous
30

Answer:

Let the breadth and length be 4x and 5x

p of rectangle = 2(l+b)

= 2(4x+5x)=90

4x+5x=45

9x = 45

x=5

Therefore breadth is 4*x= 4*5=20

length5*x=5*5=25

Area = l*b= 20*25

Area = 500


ankurpanchal: nice answer
Answered by Sauron
45

\mathfrak{\large{\underline{\underline{Answer :-}}}}

The sides of the Rectangle are 20 cm and 25 cm.

The area of the Rectangle is 500 sq.unit.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

Given :

The ratio of sides of the Rectangle = 4:5

Perimeter of Rectangle = 90 cm

To find :

The Measures of the sides of the Rectangle and It's area.

Solution :

Consider one side as 4x

Second as 5x

\boxed{\sf{2(Length + Breadth)}}

\bf{\implies} \: 2(4x + 5x) = 90

\sf{\implies} \: 8x + 10x = 90

\sf{\implies} \:18x = 90

\sf{\implies} \:x =  \dfrac{90}{18}

\sf{\implies} \: x = 5

\rule{300}{1.5}

Value of 4x

\sf{\implies} \: 4 \times 5

\sf{\implies} \: 20

Value of 5x

\sf{\implies} \: 5 \times 5

\sf{\implies} \: 25

The sides of the Rectangle are 20 cm and 25 cm

\rule{300}{1.5}

As We got the dimensions of the Rectangle, we can now find the area of the Rectangle.

\boxed{\sf{Area = Length \times Breadth}}

\sf{\implies} \: 25 \times 20

\sf{\implies} \: 500

\therefore The area of the Rectangle is 500 sq.unit.


bxnnx: at the end open the bracked
Sauron: Thanks for the correction :)
brainliann: great observation
brainliann: nice answer!!
Soumok: perfect!
ankurpanchal: superb
Sauron: Thanks a lot Soumok ❤️
Soumok: welcome ❤❤
alhaqzaid: hi
ankurpanchal: hlo
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