Question

the sides of rectangular field are in ratio 11:7 of the perimeter is 144m. find the sides​

Answer 1

Question:-

the sides of rectangular field are in ratio 11:7 of the perimeter is 144m. find the sides.

Answer:-

• The sides of rectangle are 44 m and 28 m.

To find:-

• Sides of rectangle

Solution:-

• Ratio of sides = 11:7

Put x in the ratio:-

• Length (l) = 11 x
• Breadth (b)= 7 x

$\boxed{ \underline{ \huge{perimeter = 2(l + b)}}}$

$\large{ :\implies \: 2(11x + 7x) = 144}$

$\large{ :\implies \: \: 18x = \frac{144}{2} }$

$\large{ :\implies \:18x = 72}$

$\large{ :\implies \:x = \frac{72}{18} }$

$\large{ :\implies \:x \: = 4}$

• The value of x is 4 m.

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SIDES OF RECTANGLE:-

• Length = 11x = 11×4 = 44 m
• Breadth = 7x = 7 ×4= 28m

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The sides of rectangle are 44 m and 28 m.

Answer 2

$\huge\mathbf{\fcolorbox{pink}{blue}{Solution}}$

• Let the sides of rectangle be 11x and 7x.

$\pink{➯}$ 2 ( length + breadth ) = perimeter

⟹ 2( 11x + 7x ) = 144

⟹ 36x = 144

⟹ x = 4

$\purple{➯}$ Length = 11x = 11 × 4 = 44 cm

$\purple{➯}$ Breadth = 7x = 7 × 4 = 28 cm

$\huge\mathfrak\pink{Hence , }$

$\large\bf\red{ Length = 44 cm }$

$\large\bf\red{ Breadth = 28 cm }$

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