Question

The sides of rectangular park are in ratio 4:3. If it's area is 1728m square find the cost of fencing it at rupees 2.50 per meter

Answer 1

Answer:

Step-by-step explanation:Let the length of the park be 4x and breadth be 3x.

We have,area of the park=1728 m^2

=>l×b=1728

=>4x×3x=1728

=>12x^2=1728

=>x^2=1728/12

=>x^2=144

=>x=root over 144=12

Therefore length=4x=4×12=48 m and

Breadth=3x=3×12=36 m

Perimeter =2 (l+b)=2 (48+36)=2×84=168 m

Therefore cost=Rs. 2.50×168=Rs. 420

Answer 2

Answer:

Step-by-step explanation:

Let, the sides be x.

So, the ratio would be...4x:3x.

Area = l*b

1728 = 4x*3x

1728 = 12x^2

1728/12 = x^2

144 = x^ 2

So, x = 12m (Sqrt of 144)

4x = 4*12 = 48m

3x = 3*12 = 36m

Now, Perimeter = 2 (l+b)

= 2 (48+36)

= 2 (84)

= 168m

Cost of fencing = 168*2.5

= Rs. 420