the sides of rectangular park are in the ratio 4:3 if the area is 1728 meter square find the cost of fencing it at the rate of rd 2.50 m
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2
let ratio quanrity = k
Area of rectangular park = 1728
4k × 3k = 1728
12k^2 =1728
K^2 = 144
K = 12
perimeter of park = 2( 4k + 3k)
= 2(4×12 +3×12)
= 2(48+36)
=2×84
= 168m
given, 1m fencing cost = 2.50
so, cost of 168m long fence = 168×2.50
= 420rs
Area of rectangular park = 1728
4k × 3k = 1728
12k^2 =1728
K^2 = 144
K = 12
perimeter of park = 2( 4k + 3k)
= 2(4×12 +3×12)
= 2(48+36)
=2×84
= 168m
given, 1m fencing cost = 2.50
so, cost of 168m long fence = 168×2.50
= 420rs
Answered by
3
Answer:
Step-by-step explanation:
Let, the sides be x.
So, the ratio would be...4x:3x.
Area = l*b
1728 = 4x*3x
1728 = 12x^2
1728/12 = x^2
144 = x^ 2
So, x = 12m (Sqrt of 144)
4x = 4*12 = 48m
3x = 3*12 = 36m
Now, Perimeter = 2 (l+b)
= 2 (48+36)
= 2 (84)
= 168m
Cost of fencing = 168*2.5
= Rs. 420
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