Question

The sides of rectangular plate of mass 20 kg is
5 mx 4 m placed on a horizontal table. The
pressure exerted by the block on the table is
(Take g = 10 m/s2)
(1) 10 Pa
(2) 100 Pa
(3) 20 Pa
(4) 30 Pa​

Answer 1

Answer: Option (1): 10 Pa

Explanation:

Step 1:

Mass of the rectangular block, m = 20 kg

∴ Force exerted by the block on the table = mg = 20 * 10 = 200 N ….. [since g = 10 m/s²]

Step 2:

Length of the block = 5 m  

Breadth of the block = 4 m

∴ Area of the block = length * breadth = 5 * 4 = 20 m²

Step 3:

Thus,  

The pressure exerted by the block on the table is,

= Force / Area

= 200 N / 20 m²

= 10 Pa ….. [1 N/m² = 1 Pa]  

Answer 2

Answer:

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