Question

the sides of right angled triangle are in the radio 5:12:13 and it perimeter his 120 units then the the sides are dash​

Answer 1

Answer :

• The sides are 20 units , 48 units and 52 units

Given :

• The sides of right angled triangle are in the ratio 5 : 12 : 13
• Perimeter is 120 units

To find :

• Sides

Solution :

Let the sides be

• 5x , 12x , 13x

Given that , Perimeter is 120 units so,

⟾ 5x + 12x + 13x = 120

⟾ 30x = 120

⟾ x = 120/30

⟾ x = 4

Now we have to find the sides,

• 5x = 5(4) = 20 units
• 12x = 12(4) = 48 units
• 13x = 13(4) = 52 units

Hence , The sides are 20 units , 48 units and 52 units

More Explanation :

• Perimeter of rectangle = 2(length + breadth)
• Perimeter of square = 4a
• Perimeter of parallelogram = p(a + b)
• Perimeter of triangle = 2(sum of all sides)

Answer 2

Given : The sides of right angled triangle are in the radio 5:12:13 .

Need To Find : All three sides of Right angled triangle .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❒ Let's consider the three sides of Right-Angled - Triangle be 5x , 12x & 13 x respectively.

$\dag\:\cal{As,\:We\:know\:that\::}$

$\qquad \quad \dag\:\:\bigg\lgroup \sf {\underline {Perimeter _{(\:Triangle)} = Side A + Side B + Side C }}\bigg\rgroup$

⠀⠀⠀⠀⠀Here Side A , Side B & side C are the three sides of Triangle & Perimeter of Triangle is 120 units .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \longmapsto \sf { 5x + 12x + 13x = 120 }$

$\qquad \longmapsto \sf {17x + 13x = 120 }$

$\qquad \longmapsto \sf {30x = 120 }$

$\qquad \longmapsto \sf {x =\cancel {\dfrac{120}{30}} }$

$\qquad \longmapsto \cal{\purple {\underline{x = 4\:units }}}$

Therefore ,

• First Side = 5x = 5(4) = 20 unit
• Second Side = 12x = 12(4) = 48 units .
• Third Side = 13x = 13(4) = 52 units .

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Three\:Sides \:of\:Triangle \:are\:\bf{20\:unit\:,\:48\:unit\:\&\:52\:unit}}}}$