The sides of the quadrilateral taken in order are 15cm, 20cm, 18cm and 17cm. The angle between the sides of length 15cm and 20cm is a right angle. Find area of quadrilateral.
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Answer:
Say AB=9m,BC=40m,CD=15m,DA=28m
As given that △ABC is a right angle triangle then
AC
2
=9
2
+40
2
AC=41m
Area of △ABC=
2
1
×9×40=180m
2
,
In △ACD,
Perimeter s=
2
15+28+41
=42
Area of △ADC=
s(s−15)(s−28)(s−40)
Area of △ADC=
42(42−15)(42−28)(42−40)
=126m
2
,
Area of ABCD=Area of △ABC+Area of △ACD=180+126=306m
2
.
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