the sides of the rectangular floor are in 3 ratio 4 the area of plot is 432 m square find the cost of fencing the plot at rupees 22.50.
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Let the sides of rectangular floor be 3x and 4x
Area of plot =432m
According to Condition
(3x) × (4x) =432m
= 12x = 432m
= x = 432m÷12
= x = 36
so the measure of sides will be 3x = 3×36=108 m
And 4x = 4×36=144m
To find the cost of fencing plot we need to find its perimeter
So, perimeter =2(L+B)
=2(108+114)m
=2×252m
=504m
Cost of fencing the per meter = 22.50
Cost of fencing the 504 meter = 22.50×504 =11340
Area of plot =432m
According to Condition
(3x) × (4x) =432m
= 12x = 432m
= x = 432m÷12
= x = 36
so the measure of sides will be 3x = 3×36=108 m
And 4x = 4×36=144m
To find the cost of fencing plot we need to find its perimeter
So, perimeter =2(L+B)
=2(108+114)m
=2×252m
=504m
Cost of fencing the per meter = 22.50
Cost of fencing the 504 meter = 22.50×504 =11340
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