Question

The sides of the smaller triangle out of the two similar triangles are 4 cm and 5 cm and 6 CM respectively if the perimeter of the larger triangle is 90 cm then what are the length of the sides of the larger Triangle

Answer 1

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.

Sum of ratio =4+5+6=15

Length of 1st. side. = 4×90/15=24 cms.

Length of 2nd side =5×90/15=30cms.

Length of 3rd side =6×90/15= 36cms. 

Answer 2

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.Sum of ratio =4+5+6=15

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.Sum of ratio =4+5+6=15Length of 1st. side. = 4×90/15=24 cms.

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.Sum of ratio =4+5+6=15Length of 1st. side. = 4×90/15=24 cms.Length of 2nd side =5×90/15=30cms.

Sides of larger ∆ will be in the ratio of 4 : 5 : 6 whose perimeter is 90cms.Sum of ratio =4+5+6=15Length of 1st. side. = 4×90/15=24 cms.Length of 2nd side =5×90/15=30cms.Length of 3rd side =6×90/15= 36cms.