The sides of the triangle are 56 cm, 60 cm, and 52 cm long. Then the area of the triangle is?
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9
Sides of a triangle..
, a = 56, b = 60, c = 52
s = (a + b + c)/2
⇒ s = (56 + 60 + 52)/2
= 168/2 = 84.
Area of triangle = √s(s-a)(s-b)(s-c)
= √84(84-56)(84-60)(84-52)
= √84×28×24×32 =
1344cm2 ..Answer..
Answered by
225
★ Assumption Needed:-
Let the sides be,
- ➾ Side a = 56 cm
- ➾ Side b = 60 cm
- ➾ Side c = 52 cm
★ To Calculate:-
- Area of the triangle.
★ Formula Used:-
~Semi-Perimeter
Where,
- ➾ a = Length of side a
- ➾ b = Length of side b
- ➾ c = Length of side c
~Area of the triangle
Where,
- ➾ s = semi-perimeter
- ➾ a = 8 cm = Length of side a
- ➾ b = 42 cm = Length of side b
- ➾ c = 44 cm = Length of side c
★ Calculating:-
Step1: Now we will find out the semi-perimeter so we will substitute the values in the formula. [ Semi-perimeter = a + b + c/2 ]
.°. The semi - perimeter is 84 cm.
Step2: Now to calculate the triangle area, we will again use the formula and substitute the values. [ Area of triangle = √s ( s - a ) ( s -b ) ( s - c )]
.°. The area of the triangle is 1344 cm².
★ Answer:-
- The area of the triangle is 1344 cm².
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