Question

the sides of the triangle are given by rhe sides
$\sqrt{a^{2} + b {}^{2} }$
,
$\sqrt{c ^{2} + a {}^{2} }$
and b+c what is area of the triangle

​

Answer 1

Answer:

ANSWER

It is given that, l=

b

2

+c

2

; m=

c

2

+a

2

; n=

a

2

+b

2

Now from cosine rule: cosL=

2mn

m

2

+n

2

−l

2

=

2

(c

2

+a

2

)(a

2

+b

2

)

(c

2

+a

2

)+(a

2

+b

2

)−b

2

−c

2

⇒cosL=

(c

2

+a

2

)(a

2

+b

2

)

a

2

⇒sinL=

1−cos

2

L

=

(c

2

+a

2

)(a

2

+b

2

)

b

2

c

2

+c

2

a

2

+a

2

b

2

Therefore, △=

2

mnsinL

=

2

b

2

c

2

+c

2

a

2

+a

2

b

2