Question

the sides of the triangle are in the ratio 15:13:14 and its perimeter is 168 cm . find the area of triangle.

Answer 1

HEY MATE,__________________↓↓↓

LET,THE SIDES OF A TRIANGLE BE

15x , 13x , 14x

HERE, a = 15x
b = 13x
c = 14x

SO,
THE PERIMETER OF A TRIANGLE(2S) = 168CM
a + b. + c = 168
⇒ 15x. + 13x. + 14x. = 168
⇒ 42x. = 168
⇒ x. = 4

∴ a. = 15x. = 15×4=60
b. = .13x = 13×4=52
c = 14x. = 14×4=56


SEMI PERIMETER. (S)
= 168/2=84cm.

∴ AREA = √s (s - a)(s - b)(s - c)
= √ 84(84 - 60)(84-52)(84-56)
= √ 84× 24 × 32 × 28
= √...(.approx )

SORRY I COULD NOT COMPLETE IT.

HOPE U UNDERSTAND TILL HERE.☺☺

Answer 2

Answer:

HEY MATE,__________________↓↓↓

LET,THE SIDES OF A TRIANGLE BE

15x , 13x , 14x

HERE, a = 15x

b = 13x

c = 14x

SO,

THE PERIMETER OF A TRIANGLE(2S) = 168CM

a + b. + c = 168

⇒ 15x. + 13x. + 14x. = 168

⇒ 42x. = 168

⇒ x. = 4

∴ a. = 15x. = 15×4=60

b. = .13x = 13×4=52

c = 14x. = 14×4=56

SEMI PERIMETER. (S)

= 168/2=84cm.

∴ AREA = √s (s - a)(s - b)(s - c)

= √ 84(84 - 60)(84-52)(84-56)

= √ 84× 24 × 32 × 28

= √...(.approx )

SORRY I COULD NOT COMPLETE IT.

HOPE U UNDERSTAND TILL HERE.☺☺

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