Math, asked by jidukrishnapj, 9 months ago

the sides of the triangle are in the ratio 3 5 6 and its perimeter is 70 m find the area​

Answers

Answered by Anonymous
16

\red{\bold{\underline{\underline{QUESTION:-}}}}

the sides of the triangle are in the ratio 3 5 6 and its perimeter is 70 m find the area

\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar

\red{ ☆ UPSC-ASPIRANT ☆ }

see in the picture above attach for complete solution step by step:-

Hope it helps you..!!!

_________________

Thankyou:)

Attachments:
Answered by ShashwatTSS
8

Answer:

Answer:

p = sum of sides of triangle

Let the common constant be x  

Therefore, sides of triangle 3x 5x  6x

3x + 5x + 6x = 70 m ( given )

14x = 70

x = 5

semi perimeter = 70 / 2 = 35

area of triangle =  \sqrt{s(s-a)(s-b)(s-c)}

\sqrt{35 (35- 15) ( 35- 25) (35- 30)}

= \sqrt{35(20)(10)(5)}

=\sqrt{35000}

=  50 \sqrt{14} m

Similar questions