Question

The sides of the triangle are in the ratio 3 : 5 : 6 and its perimeter is 70 m . Find the area of the triangle .

Answer 1

Answer:

perimeter = sum of sides of triangle

Let the common constant be x  

Therefore, sides of triangle 3x 5x  6x

3x + 5x + 6x = 70 m ( given: sum of sides of triangle is perimeter )

14x = 70

x = 5

The sides are

3x = 15(a)

5x= 25(b)

6x = 30(c)

semi perimeter = 70 / 2 = 35

area of triangle =  $\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{35 (35- 15) ( 35- 25) (35- 30)}$

= $\sqrt{35(20)(10)(5)}$

=$\sqrt{35000}$

=  50 $\sqrt{14}$ m