Math, asked by yashkaranradcli3378, 10 months ago

The sides of the triangles are 7,6,8. so find the area of the triangles. find area

Answers

Answered by MяƖиνιѕιвʟє
108

ɢɪᴠᴇɴ :-

  • Sides of Triangle are 7cm , 6cm , 8cm

Tᴏ Fɪɴᴅ :-

  • Area of Triangle

Sᴏʟᴜᴛɪᴏɴ :-

We know that,

Area of Triangle. = √s(s-a) (s-b) (s-c)

where,

s = Perimeter of Triangle / 2

s = (a + b + c) / 2

s = ( 8+ 7+ 6) / 2

s = 21/2 = 10.5cm

a , b, c are sides of Triangle

Now,

\tt Area \: of \: triangle =  \sqrt{s(s - a)(s - b)(s - c)}  \\  \\ \implies\tt \:    \sqrt{10.5(10.5 - 7)(10 .5 - 6)(10.5 - 8)}  \\  \\  \implies\tt \:   \sqrt{10.5 \times 3.5 \times 4.5 \times 2.5}  \\  \\  \implies\tt \:  \sqrt{413.4375}  = 20.33  {cm}^{2}

_____________________________________

Mᴏʀᴇ Fᴏʀᴍᴜʟᴀs :-

  • Area of Triangle = 1/2 × base × height

  • Area of Equilateral triangle = √3a²/4

  • Area of Isosceles Triangle = b/4 . √(4a² - b²)

  • Perimeter of Equilateral triangle = 3a
Answered by BrainlyAnswerer0687
27

{\bf{\underline{\underline{\bigstar\: Figure : }}}}\\

\:\:

\setlength{\unitlength}{1.6mm}\begin{picture}(50,20)\linethickness{0.1mm}\put(-3,-3){\line(1,1){20}}\put(36.6,-2.8){\line(-1,1){19.8}}\put(-3,-3){\line(1,0){39.5}}\put(30,6){6}\put(3,6){7}\put(15,-5){8}\end{picture}

\:\:

{\bf{\underline{\underline{\bigstar\: Given : }}}}\\

\:\:

  • \red{\footnotesize{ First\: side(a) = 7 }}\\

  • \red{\footnotesize{ Second\: side(b) = 6 }}\\

  • \red{\footnotesize{ Third\: side(c) = 8 }}\\

\:\:

{\bf{\underline{\underline{\bigstar\: To \: Find : }}}}\\

\:\:

  • \red{\footnotesize{ Area\:of\: triangle }}\\

\:\:

{\bf{\underline{\underline{\bigstar\: Solution : }}}}\\

\:\:

\orange{\footnotesize{ Semi\: perimeter(s) = \dfrac{7 + 6 + 8}{2} }}\\

\orange{\footnotesize{\implies Semi\: perimeter(s) = \dfrac{21}{2} }}\\

\orange{\footnotesize{\implies Semi\: perimeter(s) = 10.5 }}\\

\:\:

\rule{200}2

\:\:

\blue{\footnotesize{ Area\:of\: triangle = \sqrt{ S ( s - a)(s - b)(s - c)}}}\\

\blue{\footnotesize{\implies  Area\:of\: triangle = \sqrt{ 10.5 ( 10.5 - 7)(10.5 - 6)(10.5 - 8)}}}\\

\blue{\footnotesize{\implies  Area\:of\: triangle = \sqrt{ 10.5 \times 3.5 \times 4.5 \times 2.5}}}\\

\blue{\footnotesize{\implies  Area\:of\: triangle = \sqrt{413.43}}}\\

\blue{\footnotesize{\implies  Area\:of\: triangle = 20.33}}\\

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