The sides of triangle ABC are produced as shown in the figure, prove that angle CBX + angle ACY + angle BAZ = 360°
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Answer:
angle BAC + angle BCA = angle ACY........(i)
angle ABC +angle BCA = angleBAZ.........(ii)
angle BAC + angle CBA = angle ACY........(iii)
add i + ii + iii
angle ( BAC + BCA+ ABC + BCA+BAC+CBA) = angle ( CBx+ BAZ+ ACY)
angle ( 2BAC + 2BCA+ 2ABC) = angle (CBx+BAZ+ACY)
2 * 180 = angleACY+angleBAZ+angleACY
360 = angleACY + angleBAZ+ angle ACY
Answered by
1
Answer:
Step-by-step explanation:
angle BAC + angle BCA = angle ACY........(i)
angle ABC +angle BCA = angleBAZ.........(ii)
angle BAC + angle CBA = angle ACY........(iii)
add i + ii + iii
angle ( BAC + BCA+ ABC + BCA+BAC+CBA) = angle ( CBx+ BAZ+ ACY)
angle ( 2BAC + 2BCA+ 2ABC) = angle (CBx+BAZ+ACY)
2 * 180 = angleACY+angleBAZ+angleACY
360 = angleACY + angleBAZ+ angle ACY
...............
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