Question

the sides of triangle are 28cm 21 cm and 35 cm then the length of the altitude corresponding to the largest side of the triangle is

Answer 1

i think the length of the altitude will be =1911/4 cm.

Answer 2

Area of triangle
$= \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{(28 + 21 + 35)(84 - 28)(84 - 21)(84 - 35)} \\ = \sqrt{84 \times 56 \times 63 \times 49} \\ = 588 \sqrt{42} cm.$
= 1/2 × b × h
= 1/2 × 35 × h = 588 × sq. root of 42.
=>h = 217.7528874665cm.


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