Question

The sides of triangle are 3x+2, 5x-3 and 4x+6
find its perimeter
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Answer 1

Answer:

Given Data:-

• 1st side of the triangle = (3x + 2) units
• 2nd side of the triangle = (5x - 3) units
• 3rd side of the triangle = (4x + 6) units

To Find:-

Perimeter of the triangle.

________________...

We know,

Perimeter of triangle = Sum of all sides

⬆

(Or any closed figure)

Since, the value of the sides are algebraic expressions, therefore, we've to add them.

(Note: I am using horizontal method of addition, you can prefer both, column method or this method.)

So,

Perimeter of the triangle:-

(3x + 2) + (5x - 3) + (4x + 6) units

(Written as per the formula)

➡ 3x + 2 + 5x - 3 + 4x + 6 units

(Brackets have been demolished, since we've to simplify the Expressions to get the perimeter)

➡ (3x + 5x + 4x) + [2 + (-3) + 6] units

(We've collected the like terms near and kept them in brackets)

➡ (12x) + (2 - 3 + 6) units

(Simplification 1; (+) + (-) = (-))

➡ 12x + (2 + 3) units

(Simplification 2; followed the rule of BODMAS or simply DMAS)

➡ 12x + 5 units

(Solution)

_______________...

∴ Perimeter of the triangle is (12x + 5) units.

Answer 2

Question

The sides of triangle are 3x+2, 5x-3 and 4x+6.Find its perimeter.

Answer

Given :-

1st side : 3x + 2

2nd side : 5x - 3

3rd side : 4x + 6

To find :-

Perimeter : ??

Formula used :-

Perimeter of triangle : Sum of all its side

According to the question,

Perimeter of triangle = Sum of all its side

= 3x + 2 + 5x - 3 + 4x + 6

= 3x + 5x + 4x + 2 - 3 + 6

= 12x + 5

.°.The perimeterof triangle is 12x + 5.