Question

The sides of triangle are 56 cm,60 cm,62 cm long.then what is the area

Answer 1

Solution.

a = 56cm, b = 60cm , c = 62cm.

S = a+b+c/2
= 56+60+62/2
= 178/2
= 89cm.

Area of triangle, using heron's formula
S =
$\sqrt{s(s - a)(s - b)(s - c)}$
S =
$\sqrt{89(89 - 56)(89 - 60)(89 - 62).}$
S =
$\sqrt{89 \times 33 \times 29 \times 27}$
S =
$\sqrt{89 \times 11 \times 3 \times 29 \times 3 \times 3 \times 3}$
S =
$3 \times 3 \sqrt{89 \times 11 \times 29}$
S =
$9 \sqrt{2839 \: } {cm}^{2}$