Question

the sides of triangle are given by an equation y-2=0; y+1=3(x-2)=0 and x+2y=0 find graphically a) area of triangle. b)the coordinates of the vertices of the triangle​

Answer 1

Step-by-step explanation:

MATHS

The sides of a triangle are given by the equation y−2=0,y+1=3(x−2) & x+2y=0. Find graphically the area of triangle.

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ANSWER

x+2y=0⟶(i)

y−2=0⟶(ii)

y+1=3(x−2)(iii)

solving (i)&(ii)

y=2

x=−4

∴A=(−4,2)

solving (ii)&(iii)

y=2 ⇒B=(3,2)

x=3

solving (i)&(iii)

⇒y+1=3(−2y−2)

⇒y+1=−6

⇒7y=−7

⇒y=−1

⇒x=2

∴c=(2,−1)

⇒AB=

49+0

=7

Distance of c from AB=h

=3units

∴ Area =

2

1

×7×3=

2

21

=10.5squnits

Hence, the answer is 10.5squnit.