The sides of triangle are in ratio 1/2:1/3:1/4 and itsperimeter is 104 cm. The length of the longest side is
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Answered by
52
Let the sides are x/2,x/3,x/4
A/Q,
x/2+x/3+x/4=104. [104cm is it's perimeter]
=>(6x+4x+3x)/12=104
=>13x=104*12
=>x=(104*12)/13
=>x=96
Length of the longest side=x/2=96/2=48cm
A/Q,
x/2+x/3+x/4=104. [104cm is it's perimeter]
=>(6x+4x+3x)/12=104
=>13x=104*12
=>x=(104*12)/13
=>x=96
Length of the longest side=x/2=96/2=48cm
Answered by
15
Let the variable is "x"
So according to the question;
The three sides of the triangle will be,
= x/2 ; x/3 ; x/4
And the total perimeter of the triangle is 104 cm
So;
x/2 + x/3 + x/4 = 104
6x+4x+3x / 12 = 104
13x/12 = 104
x= 104×12 /13
x= 96
The length of the three sides will be;
= x/2 cm ; x/3 cm ; x/4 cm
= 48 cm ; 32 cm ; 28 cm
So the length of the triangle's longest side is 48 cm.
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