Question

The sides of triangle are in ratio 2:3:5. If their perimeter is 120. Find the sides
of the triangle.

Answer 1

Answer:

let the sides of the triangle be 2x,3x,5x

perimeter of triangle is = sum of all sides of the triangle = 2x + 3x + 5x = 120

10x = 120

x = 12

2x = 2*12 = 24

3x = 3*12 = 36

5x = 5*12 =60

Explanation:

hope this helps you.

Answer 2

Answer:

a+b+c/2 = 2x+3x+5x=120

10x = 120

x = 120/10

x = 12

2x = 2× 12 = 24

3x = 3× 12= 36

5x = 5 × 12 = 60

24+36+60/2= 120 /2 =60

√s×(s-a) (s-b)( s-c)

60×60-24×60-36×60-60

60 ×36 × 24 ×0

72√10