Question

the sides of triangle are in ratio 3:5:7 and its perimeter is 600 cm find the area of triangle​

Answer 1

if the side are in ratio 3:5:7

perimeter is 600cm

let number x

3x+5x+7x=600

15x=600

x=40

each side

3x=3×40=120cm

5x=5×40=200cm

7x=7×40=280cm

area=120×200×280=

6720000cm³

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Answer 2

The area of triangle​ is 10392.3048 sq.cm.

Step-by-step explanation:

We are given that the sides of triangle are in ratio 3:5:7

Let the ratio be x

So, Sides are 3x , 5x and 7x

Perimeter of triangle = Sum of all sides = 3x+5x+7x=15x

We are given that its perimeter is 600 cm

So, $15 x = 600$

$x=\frac{600}{15}$

x=40

Sides are 3x=3(40)=120 cm , 5x = 5(40)=200 cm and 7x =7(40)=280 cm

a= 120 cm

b = 200 cm

c=-280 cm

Area of triangle =$\sqrt{s(s-a)(s-b)(s-c)}$

$s=\frac{a+b+c}{2}$

$s=\frac{120+200+280}{2}$

s=300

$Area = \sqrt{300(300-120)(300-200)(300-280)}$

Area =  10392.3048 sq.cm.

Hence The area of triangle​ is 10392.3048 sq.cm.