Question

The sides of triangle are in ratio of 18 16 and 25 and its parameter is 590 find the area of this Triangle

Answer 1

14356 is the area of the triangle

Answer 2

$14355cm^2$

Step-by-step explanation:

Let the side be x,

then $18\times x=18x$

       $16\times x=16x$ and

       $25\times x=25x$

Perimeter=590

$18x+16x+25x=590$

$59x=590\\x=10$

so,length of first side of triangle $a=18\times10=180cm$

    length of second side of triangle $b=16\times10=160cm$

    length of third side of triangle $c=25\times10=250cm$

semi perimeter of triangle= $S=\frac{a+b+c}{2}=\frac{180+160+250}{2}$

                                          $S=\frac{590}{2}\\S=295$

Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)$

                           $\sqrt{295(295-180)(295-160)(295-250)} \\\sqrt{295(115)(135)(45)$

                           $225\sqrt{4071} \\=14355cm^2$