Question

The sides of triangle are in the ratio 6:8:10. If the perimeter of the triangle is 288cm find the i)difference between the longest and shortest sides​

Answer 1

Answer:

shortest side is 72cm

Longest side is 120cm

6 + 8 + 10 = 24

288/24 = 12

longest side = 10 x 12 =120

shortest side = 6 x 12 = 72

Answer 2

AnswEr:-

i) Difference between the longest nd shortest side = 48 cm.

$\rule{200}{1}$

Given:-

• Ratio of sides = 6 : 8 : 10
• Perimeter of triangle = 288 cm

To find:-

• Difference between longest side & shortest side of triangle.

Solution :-

Let the three sides of triangle be 6y , 8y & 10y respectively.

Now we know,

☛ Perimeter of triangle = Sum of sides

↠ Perimeter = 6y + 8y + 10y

↠ Perimeter = 24y

According to question:-

As,perimeter given = 288 cm

⇒ 24y = 288

⇒ y = 288/24

⇒ y = 12

⋆ SIDES OF TRIANGLE:-

⇒ One side = 6y = 6(12) = 72 cm

⇒ Second side = 8y = 8(12) = 96 cm

⇒ Third side = 10y = 10(12) = 120 cm

⋆ DIFFERENCE :-

☛ Difference = 10y - 6y

↠ Difference = 4y cm

↠ Difference = 4(12) cm

↠ Difference = 48 cm

Therefore,difference between longest & shortest side = 48 cm.