Question

the sides of triangle field are 41 m 40 m and 9m and the no of row beds that can be prepared in the field . if each row beds on average needs 900 m^ 2 ............Hint ... the no of row beds = area of triangle field / area of 1 rowbed ... plz solve with full solution ... correct and full solution urgently ...... plz plz plz any maths expert help .....

Answer 1

let the sides of the triangle be s₁ s₂&s₃ and the semi perimeter be sₚ
as per condition
s₁=41m
s₂=40m
s₃=9m
∴sₚ= (s₁+s₂+s₃)/2
sₚ=(41+40+9)/2
sₚ=45
area of the Δ = √sₚ(sₚ-s₁)(sₚ-s₂)(sₚ-s₃)
=√45(4)(5)(36)
=±(3×5×2×6)
=180m²[∵length can never be negetive]
=(180×100×100)cm²
if each flower bed's area is 900cm²
then number of flower brds that can be placed=(180×100×100)/900
=2000