The sides of triangular field are 55m, 300m and 300m. It's area is equal to (7/15)th area of circular park. What is perimeter (in m) of the circular park (corrected to one deciml place)? (Take pi = 22/7)
Answers
triangular field are55m.300and300m.itsarea is equal to (7/15)th area of circular park
Given : The sides of triangular field are 55m, 300m and 300m. It's area is equal to (7/15)th area of circular park.
To Find : perimeter (in m) of the circular park (corrected to one decimal place)
Solution:
The sides of triangular field are 55m, 300m and 300m
s = (55 + 300 + 300) / 2 = 327.5 m
Area using Hero Formula
A = √s(s - a)(s - b)(s - c) =
= √(327.5)(327.5 - 55)(327.5 - 300)(327.5 - 300) = 8215.3 m²
area is equal to (7/15)th area of circular park.
=> 8215.3 = 7/15 Circle Area
=> Circle Area = 8215.3 * 15 / 7
]=> π R² = 8215.3 * 15 / 7
=> R = 74.84
perimeter of the circular park = 2 ( 22/7) * 74.84 = 470.4 m
perimeter (in m) of the circular park (corrected to one decimal place) 470.4 m
Learn More:
find perimeter and area of shaded region as show in figure - Brainly.in
https://brainly.in/question/7362497
the perimeter of a semicircular protractor with diameter 10cm ...
https://brainly.in/question/13217507