Math, asked by dkchindia, 11 months ago

the sides of triangular park are 60m 112m and 164m the cost of levelling the park @ rate 8.5 per metre square is​

Answers

Answered by Anonymous
63

\large{\underline{\underline{\mathrm{\red{Answer-}}}}}

Cost of levelling it at the rate of 8.5 per metre square = Rs. 17136

\large{\underline{\underline{\mathrm{\red{Explanation-}}}}}

We've to find the area of by using heron's formula,

\huge{\boxed{\rm{S\:=\:\dfrac{a+b+c}{2}}}}

\begin{lgathered}\bold{Here} \begin{cases}\sf{S\:refers\:to\:semi\:perimeter} \\ \sf{a\:=\:60\:m}\\ \sf{b\:=\:112\:m} \\ \sf{c\:=\:164\:m}\end{cases}\end{lgathered}

So let's find semi perimeter first,

\implies S = \dfrac{60\:+\:112\:+\:164}{2}

\implies S = \cancel{\dfrac{336}{2}}

\implies S = 168 m

Now, herons formula :

\large{\boxed{\rm{\red{\sqrt{s(s - a)(s - b)(s - c)}}}}}

Putting the values,

\implies \sqrt{168(168 - 60)(168 - 112)(168 - 164)}

\implies \sqrt{168(108)(56)(4)}

\implies \sqrt{4064256}

\implies 2016 m²

\therefore Area of triangular plot is 2016 m²

Now cost of levelling it at the rate of 8.5 per metre square :

\implies Area of triangular plot × 8.5

\implies 2016 × 8.5

\implies Rs. 17136

Cost of levelling it at the rate of 8.5 per metre square = Rs. 17136

Answered by EliteSoul
124

Answer:

\bold\red{Cost\:of\:levelling} = \bold{Rs.17,136}

Step-by-step explanation:

\bf{Given:-}\begin{cases}\sf{a = 60\:m}\\\sf{b = 112\:m}\\\sf{c = 164\:m}\\\sf{Rate = 8.5\:per\:{m}^{2}}\\\sf{Cost\:of\:levelling=?}\end{cases}

We know that,

\small{\boxed{\bold\purple{Area\:of\:triangle = \sqrt{s(s-a)(s-b)(s-c)}}}}

Where, s = half of perimeter of triangle.

\Rightarrow\sf s =\dfrac{60 + 112 + 164}{2} \\\\\Rightarrow\sf s =\cancel{\dfrac{336}{2}}\:m \\\\\Rightarrow{\boxed{\sf{s = 168\:m}}}

\rule{300}{1}

\Rightarrow\sf Area =\sqrt{168(168-60)(168-112)(168-164)} \\\\\Rightarrow\sf Area =\sqrt{168 \times 108 \times 56 \times 4} \\\\\Rightarrow\sf Area =\sqrt{4064256}\:{m}^{2} \\\\\Rightarrow{\boxed{\bold\red{Area = 2016\:{m}^{2} }}}

\rule{300}{1}

\Rightarrow\sf Cost = Area \times Rate \\\\\Rightarrow\sf Cost = Rs.(2016 \times 8.5) \\\\\Rightarrow{\boxed{\bold\red{Cost = Rs.17136}}}

\therefore\bold{Cost\:of\:levelling = Rs.17,136}

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