The sides (other than hypotenuse) of a right triangle are in the ratio 3:4
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Step-by-step explanation:
The double cone so formed by revolving this right-angled triangle ABC about its hypotenuse is shown in the figure.
Hypotenuse, AC = 3 2= 9+16 = 25=5 cm
Area of ΔABC= 21 ×AB×AC⇒ 21 ×AC×DB= 21×4×3⇒ 21×5×DB=6
So, DB = 51 =2.4 cm
The volume of double cone = Volume of cone 1 + Volume of cone = 3πr 2 1
+
3
1
πr
2
h
2
=
3
1
πr
2
[h
1
+h
2
]=
3
1
πr
2
[DA+DC]
=
3
1
×3.14×2.4
2
×5
=30.14 cm
3
The surface area of double cone = Surface area of cone 1 + Surface area of cone 2
=πrl
1
+πrl
2
=πr[4+3]=3.14×2.4×7
=52.75 cm
2
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