The sides PQ and PR are produced to S and T respectively and angle SQR < angle TRQ . Prove that PR > PQ
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Answered by
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Proved below.
Step-by-step explanation:
Given:
Here, sides PQ and PR are produced to S and T respectively.
And ∠ SQR < ∠ TRQ
so 180° - ∠ SQR > 180° - ∠ TRQ [Subtracting both sides by 180°]
or ∠ PQR > ∠ PRQ
hence PR > PQ [as side oppsoite to greater angle is greater]
NOTE : You may have in your mind that how 180° - ∠SQR > 180° - ∠TRQ,
let us take an example,
3 < 4 but 10 − 3 > 10 − 4
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