Question

the sides triangle in the ratio of4;5:5and perimatter as168 cm find ares
of triangle

Answer 1

Answer: 864 cm^2

Step-by-step explanation:

Ratio of sides of triangle = 4:5:5

Perimeter (p) of triangle = 168 cm

P of ∆ = sum of sides

=> 168 = 4x + 5x + 5x

=> 168 = 14x

=> x = 168/14

=> x = 12

=> 4x = 48 & 5x = 60

Sides are in ratio 4:5:5

=> two sides are equal

=> It is an isosceles ∆

=> base(b) = 4x = 48 cm

=> height (h) = √[(5x)^2 - (4x)^2] = √(60^2 - 48^2) = √(3600 - 2304)

=> height (h) = √1296 = 36 cm

Now,

Area of ∆ = 1/2 × b × h = 1/2 × 48 × 36 = 864 cm^2

Area of ∆ = 864cm^2

Answer 2

Answer:

Step-by-step explanation:

Let the sides be 4x. 5x and 5x.

4x+5x+5x= 14x=168

X=12

Length of sides are 48, 60,60

h^2=60^2-24^2

=3600-576

=3024

h=54.99

Area=1/2× 48×54.99

=1319.76