Math, asked by svetajayaprakash23, 10 months ago

the simple interest accrued on an amount of ₹22,500 at the end of 4 years is ₹10,800.What would be the compound interest accrued on the same amount at the same rate of interest at the end of 2 years?​

Answers

Answered by haridasan85
3

Answer:

SI:

R=100xI/PN=100x10800/22500x4

= 12%

CI = 22500 (1 +12/100) 2-22500

=28224-22500 = Rs 5724

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