the simple interest accrued on an amount of ₹22500 at the end of 4 years is ₹10,800 what would be the compound interest accrued on the same amount at the same rate of interest at the end of 2 years?
₹ 16,908
₹5724
₹28,224
₹8586
please explain step by step don't spam
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s.i.=pnr / 100
10800 = 22500 × 4 × r / 100
r = 12%
c.i. = p[ (1+r/100)^n -1 ]
c.i.= 22500 [ (1+ 12/100)^2 - 1 ] { given n= 2}
c.i.= rs.5724
10800 = 22500 × 4 × r / 100
r = 12%
c.i. = p[ (1+r/100)^n -1 ]
c.i.= 22500 [ (1+ 12/100)^2 - 1 ] { given n= 2}
c.i.= rs.5724
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